t^2-8t+22=

Solution for t^2-8t+22= equation:

Simplifying
t2 + -8t + 22 = 0

Reorder the terms:
22 + -8t + t2 = 0

Solving
22 + -8t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-22' to each side of the equation.
22 + -8t + -22 + t2 = 0 + -22

Reorder the terms:
22 + -22 + -8t + t2 = 0 + -22

Combine like terms: 22 + -22 = 0
0 + -8t + t2 = 0 + -22
-8t + t2 = 0 + -22

Combine like terms: 0 + -22 = -22
-8t + t2 = -22

The t term is -8t.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8t + 16 + t2 = -22 + 16

Reorder the terms:
16 + -8t + t2 = -22 + 16

Combine like terms: -22 + 16 = -6
16 + -8t + t2 = -6

Factor a perfect square on the left side:
(t + -4)(t + -4) = -6

Can't calculate square root of the right side.

The solution to this equation could not be determined.